LINEAR EQUATIONS IN ONE VARIABLE(LECTURE 2)

21ST APRIL,20

Dear students
Welcome to the class!!

How was the test yesterday??
I hope you all have noted down the errors (if any)!!
This will help you ace your performance!!

Guidelines for the class:

1. Note down  the work in your register on a regular basis.

2. Please feel free to ask, if you have any doubt by dropping a message in the comment box.

3. Make a column on the right hand side, if you need to do any rough work

4..Write today's date.

5.Write the chapter number and name.

6.Text in Blue has to be noted down.

let's recall the  learning outcomes we covered  yesterday:

What is a linear equation in one variable and its solution.

Write down Today's Learning Outcomes

I will be able to:

1.Recall what is a linear equation in one variable.

2. solve  linear equation in one variable 

Let's start with our class.

How to solve linear equation in one variable ?

There are 2 methods to solve:

✴ We assume that the two sides of the equation are balanced. We perform the same mathematical operations on both sides of the equation, so that the balance is not disturbed

Click on the link to view the method

As you saw in the link, this method in not used in common.

✴✴   Transpose method

Click on the link to view the method

Now, look at the eg. given below

eg1. Solve 2y + 9 = 4 (note down)

Solution: Transposing 9 to RHS

2y  = 4 – 9 or 2y  = – 5

Dividing both sides by 2, 

y =- 5/ 2  is the solution

eg2 Solve  15/ 4 – 7x = 9 (Complete it)

Solution: We have 15/ 4 – 7x = 9
 

or – 7x = 9 ................... (transposing 15/ 4 to R H S)
or – 7x =..............(solving RHS)
or x =................... (dividing both sides by – 7)

 

Do the following questions as CW

Please check your answers. Give a 😊 in  your notebook if you get all correct.
Q1     II     Q2  II       Q3 I

                                                EX2.1
(USE TRANSPOSE METHOD)

                                   

YOU ARE ENCOURAGED TO SOLVE ON YOUR OWN AND THEN REFER TO THE ANSWERS GIVEN BELOW .

ANSWERS
A 7 ) 2x =18 x 3 
=>2 x = 54 
 => x = 54/2
=>  x= 27

A8)  y = 1.5 x 1.6
=>  y= 2.4

A9)  7x = 16 +9 
=> 7x  = 25 
=> x = 25/7

A10) 14y = 13 +8 
=> 14y = 21
 => y = 21/14 
=> y = 3/2( dividing numerator and denominator by 7)

A11)  6p = 9 -17 
=> 6p = -8 
 => p = - 8/6
 => p = -4/3 (dividing numerator and denominator by 2)

A12 ) x/3 = 7/15 -1 
=> x/3 = (7 -15)/ 15 
=> x/3 = -8/15 
=> x = (-8x3)/15
 => x = -24/15
 => x= -8/5

We end our class here 

Take care and keep safe!!

   Ex 2.1 Q1 to 6